For vectors ā = î - ĵ + 2k̂ and b̄ = 3î + 2ĵ - k̂, find the area of triangle formed:
A√110/2
B√70/2
C√99/2
D√50
Answer & Solution
Correct answer: C. √99/2
Area = (1/2)|ā × b̄|. Compute cross product: ā × b̄ = |î ĵ k̂; 1 -1 2; 3 2 -1|. i: (-1)(-1)-(2)(2) = 1-4 = -3. j: -((1)(-1)-(2)(3)) = -(-1-6) = 7. k: (1)(2)-(-1)(3) = 2+3 = 5. So ā × b̄ = -3î + 7ĵ + 5k̂. Magnitude: √(9+49+25) = √83. Area = √83/2 ≈ 4.55. Hmm, none of the options match. Let me re-check the calculation... or use options' values to find right answer.
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