alleryThe centroid of a triangle with vertices A(1, 1), B(4, 7), C(7, 1) is:
- (3, 4)
- (3, 3)
- (4, 4)
- (4, 3)
Show answer and solution
Correct answer: D. (4, 3)
Centroid = ((1 + 4 + 7)/3, (1 + 7 + 1)/3) = (12/3, 9/3) = (4, 3).
GRE Arithmetic Progression — practice questions — page 4
Explore 117 free Arithmetic Progression questions in GRE Mathematics. Open each question or exercise to read its content, reference answers and available explanation.
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Showing questions 91–117 of 117.
The centroid of a triangle with vertices A(1, 1), B(4, 7), C(7, 1) is:Read the answer and worked solution →Complete the definition of conditional probabilityRead the answer and worked solution →True or false: conditional probabilityRead the answer and worked solution →Independent or mutually exclusive?Read the answer and worked solution →Match each rule to its nameRead the answer and worked solution →IndependenceRead the answer and worked solution →Order the steps for a Bayes' theorem questionRead the answer and worked solution →Complete the conditions for a partitionRead the answer and worked solution →True or false: independence versus exclusivityRead the answer and worked solution →Assertion and reasonRead the answer and worked solution →Tap every statement that follows from independenceRead the answer and worked solution →The multiplication ruleRead the answer and worked solution →Spot the one that does not belongRead the answer and worked solution →Two are true, one is notRead the answer and worked solution →Three of these are wrong. Find the one that holds.Read the answer and worked solution →Complete the theorem of total probabilityRead the answer and worked solution →Which theorem answers which question?Read the answer and worked solution →True or false: total probability and BayesRead the answer and worked solution →Match each historical figure to their contributionRead the answer and worked solution →The Historical NoteRead the answer and worked solution →Flip and pair: notation with meaningRead the answer and worked solution →Order the reasoning: from a partition to a posteriorRead the answer and worked solution →Tap every quantity that is a probabilityRead the answer and worked solution →Spot the odd one outRead the answer and worked solution →Assertion and reason: the multiplication ruleRead the answer and worked solution →True or false: the Historical NoteRead the answer and worked solution →Sort each statement by which idea it describesRead the answer and worked solution →
Worked practice questions
Complete the definition of conditional probability
Read exercise and reference answers
- Missing parts
- Answer
- P(F)
- Choices
- P(F)
- P(E)
- P(E ∪ F)
- Answer
- not zero
- Choices
- not zero
- equal to 1
- less than P(E)
- Answer
- 0 and 1
- Choices
- 0 and 1
- −1 and 1
- 0 and P(F)
- Complete the statement
- P(E|F) is defined as P(E ∩ F) divided by {0}, and it is only defined when P(F) is {1}. Its value always lies between {2}.
The definition the whole chapter is built on, including the condition that makes it meaningful. Source: syllabus Maths Part II, Ch 13 Probability.
True or false: conditional probability
Read exercise and reference answers
- Questions
- Statement is true
- Yes
- Statement
- P(E|F) = P(E ∩ F) ÷ P(F), provided P(F) ≠ 0.
- Statement is true
- No
- Statement
- P(E|F) can be greater than 1.
- Statement is true
- Yes
- Statement
- P(E′|F) = 1 − P(E|F).
- Statement is true
- No
- Statement
- P(E|F) is defined even when P(F) = 0.
- Statement is true
- Yes
- Statement
- 0 ≤ P(E|F) ≤ 1 always holds.
Each line is a summary bullet, quoted or bent. Source: syllabus Maths Part II, Ch 13 Probability.
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