As per your syllabus, what is the PE of a 200 g cricket ball at a height of 10 m (taking g = 10 m/s²)?
- 200 J
- 20 J (= 0.2 × 10 × 10)
- 2000 J
- 2 J
Show answer and solution
Correct answer: B. 20 J (= 0.2 × 10 × 10)
As per your syllabus, PE = mgh = 0.2 kg × 10 m/s² × 10 m = 20 J. Mass must be in kg.