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DSSSB TGT C9potentialconservation — practice questions

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C9potentialconservation questions and exercises with answers

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Worked practice questions

As per your syllabus, what is the PE of a 200 g cricket ball at a height of 10 m (taking g = 10 m/s²)?

  1. 200 J
  2. 20 J (= 0.2 × 10 × 10)
  3. 2000 J
  4. 2 J
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Correct answer: B. 20 J (= 0.2 × 10 × 10)

As per your syllabus, PE = mgh = 0.2 kg × 10 m/s² × 10 m = 20 J. Mass must be in kg.

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