alleryStart learning →As per your syllabus, what is the PE of a 200 g cricket ball at a height of 10 m (taking g = 10 m/s²)?
A200 J
B20 J (= 0.2 × 10 × 10)
C2000 J
D2 J
Answer & Solution
Correct answer: B. 20 J (= 0.2 × 10 × 10)
As per your syllabus, PE = mgh = 0.2 kg × 10 m/s² × 10 m = 20 J. Mass must be in kg.
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