alleryHow many ways can 7 distinct people queue in a line (the value of 7!)?
- 720
- 49
- 840
- 5040
Show answer and solution
Correct answer: D. 5040
7! = 7 x 6 x 5 x 4 x 3 x 2 x 1 = 5040.
CA Foundation Seating Arrangements — practice questions — page 3
Explore 63 free Seating Arrangements questions in CA Foundation Quantitative Aptitude. Open each question or exercise to read its content, reference answers and available explanation.
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Showing questions 61–63 of 63.
How many ways can 7 distinct people queue in a line (the value of 7!)?Read the answer and worked solution →The number of ways to seat r of n distinct people in r chairs in a row isRead the answer and worked solution →A 4-seat bench holds 3 men and 1 woman, who must take an end seat. How many seatings?Read the answer and worked solution →
Worked practice questions
The number of ways to seat r of n distinct people in r chairs in a row is
- n!/(r + 1)!
- n!/(r!(n - r)!)
- n!/(n - r)!
- n!/(2(n - r)!)
Show answer and solution
Correct answer: C. n!/(n - r)!
Choosing and ordering r from n gives n x (n - 1) x ... x (n - r + 1), which equals n!/(n - r)!.
A 4-seat bench holds 3 men and 1 woman, who must take an end seat. How many seatings?
- 6
- 24
- 12
- 18
Show answer and solution
Correct answer: C. 12
The woman has 2 end seats and the 3 men fill the rest in 3! = 6 ways, giving 12.
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