alleryStart learning →The number of ways to seat r of n distinct people in r chairs in a row is
An!/(r + 1)!
Bn!/(r!(n - r)!)
Cn!/(n - r)!
Dn!/(2(n - r)!)
Answer & Solution
Correct answer: C. n!/(n - r)!
Choosing and ordering r from n gives n x (n - 1) x ... x (n - r + 1), which equals n!/(n - r)!.
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