BITSAT Thermodynamics — practice questions
36 free MCQs with worked solutions. Tap any question for the answer + explanation, or practice them all in the app.
Practice BITSAT Thermodynamics in the app →The first law of thermodynamics is mathematically expressed as:In an isothermal process for an ideal gas, which thermodynamic quantity remains constant?For an ideal gas expanding isothermally from volume $V_1$ to $V_2$ at temperature $T$, the work done by the gaFor an adiabatic process involving an ideal gas, which quantity is constant?A Carnot engine operates between a hot reservoir at $T_1 = 500$ K and a cold reservoir at $T_2 = 300$ K. The eFor an ideal gas, the relation between molar heat capacities is $C_p - C_v = R$. Why is $C_p$ always greater tThe first law of thermodynamics is essentially a statement of:Work done in an isothermal process for ideal gas:In an adiabatic process, the heat exchanged with surroundings is:The ratio Cp/Cv is denoted by:For an ideal gas, Cp − Cv equals:In an ISOCHORIC process, work done equals:For an adiabatic process on ideal gas: PV^γ = ?Internal energy change ΔU for an ideal gas depends ONLY on:In an isothermal expansion of ideal gas, the work done BY the gas is +500 J. The heat absorbed by the gas is:A monatomic ideal gas has γ = 5/3. For an adiabatic process, P₁V₁^γ = P₂V₂^γ. If V₂ = 8V₁, find P₂/P₁:1 mole of ideal gas (Cv = 3R/2) is heated at constant volume from 300 K to 600 K. Heat absorbed:For a monatomic ideal gas in isobaric expansion from V₁ to 3V₁, find ΔT/T₁:In a cyclic process, ΔU equals:The slope of an isothermal curve in PV diagram (dP/dV)_T equals:The slope of an adiabatic curve in PV diagram (dP/dV)_adiabatic equals:For a Carnot engine operating between T_h = 600 K and T_c = 300 K, efficiency is:A gas absorbs 500 J of heat and does 200 J of work. Change in internal energy:For a diatomic ideal gas (γ = 7/5), molar Cv equals:Isothermal bulk modulus of an ideal gas equals:Adiabatic bulk modulus of ideal gas equals:In a free expansion of ideal gas (into vacuum), the temperature:An ideal gas undergoes isobaric expansion. Q = 100 J, W = 40 J. Find ΔU:For an adiabatic process of an ideal gas, TV^(γ-1) = constant. If T₁ = 300 K and V₂ = 2V₁ for γ = 5/3, then T₂In a Carnot cycle, heat absorbed at hot reservoir is 1000 J. Efficiency 25%. Heat rejected at cold reservoir:For polytropic process PV^n = constant, n = 0 means:Two identical containers contain ideal gas at temperatures T₁ and T₂. The walls suddenly become porous, gases In which process is heat capacity infinite for ideal gas?A heat engine operates with 20% efficiency between two reservoirs. If T_h = 500 K, find T_c (for maximum/CarnoAn ideal gas undergoes isothermal expansion at 300 K from V = 1 to V = 2. Heat absorbed (n = 1):A diatomic ideal gas at 27°C is compressed adiabatically to ½ its volume. Find final temperature (γ = 7/5):