1 mole of ideal gas (Cv = 3R/2) is heated at constant volume from 300 K to 600 K. Heat absorbed:
AnRT/2
B900 R
C300 R
D450 R
Answer & Solution
Correct answer: D. 450 R
At constant volume: Q = nCvΔT = 1 × (3R/2) × (600 - 300) = 1.5R × 300 = 450R.
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