An ideal gas undergoes isothermal expansion at 300 K from V = 1 to V = 2. Heat absorbed (n = 1):
AR × 300 × ln(1/2)
BR × 300
CR × 300 × ln 2
DR × 600
Answer & Solution
Correct answer: C. R × 300 × ln 2
In isothermal expansion at T, Q = W = nRT ln(Vf/Vi) = 1 × R × 300 × ln(2/1) = 300R ln 2 ≈ 208R J.
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