Two identical containers contain ideal gas at temperatures T₁ and T₂. The walls suddenly become porous, gases mix. Final temperature (ignoring container heat capacity):
A(T₁² + T₂²)/(T₁+T₂)
B√(T₁T₂)
CT₁T₂/(T₁+T₂)
D(T₁ + T₂)/2
Answer & Solution
Correct answer: D. (T₁ + T₂)/2
Conservation of internal energy: nCvT₁ + nCvT₂ = 2nCvT_f → T_f = (T₁ + T₂)/2. (Assuming same n and same Cv.)
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