A monatomic ideal gas has γ = 5/3. For an adiabatic process, P₁V₁^γ = P₂V₂^γ. If V₂ = 8V₁, find P₂/P₁:
A1/4
B1/8
C1/32
D32
Answer & Solution
Correct answer: C. 1/32
P₂/P₁ = (V₁/V₂)^γ = (1/8)^(5/3) = 8^(-5/3) = (2³)^(-5/3) = 2^(-5) = 1/32.
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