A monatomic ideal gas has γ = 5/3. For an adiabatic process, P₁V₁^γ = …

Question

A monatomic ideal gas has γ = 5/3. For an adiabatic process, P₁V₁^γ = P₂V₂^γ. If V₂ = 8V₁, find P₂/P₁:

Accepted Answer

C. 1/32

We have P₂/P₁ = (V₁/V₂)^γ.
That is P₂/P₁ = (1/8)^(5/3).
That is P₂/P₁ = 8^(-5/3).
That is P₂/P₁ = (2³)^(-5/3).
That is P₂/P₁ = 2^(-5).
So P₂/P₁ = 1/32.

Answer

1/4

Answer

1/8

Answer

32

A monatomic ideal gas has γ = 5/3. For an adiabatic process, P₁V₁^γ = P₂V₂^γ. If V₂ = 8V₁, find P₂/P₁:

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