A mass on a spring obeys d²x/dt² + ω²x = 0 (SHM). The period of oscillation is:
- $2\pi \omega$ (inverse)
- $T = 2\pi/\omega$ (the period formula)
- $T = 1/\omega$ (frequency reciprocal)
- $T = \omega^2$ (squared)
Show answer and solution
Correct answer: B. $T = 2\pi/\omega$ (the period formula)
**SHM:** x(t) = A cos(ωt + φ). Period T = 2π/ω.
Frequency f = ω/(2π) = 1/T.