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A mass on a spring obeys d²x/dt² + ω²x = 0 (SHM). The period of oscillation is:
A$2\pi \omega$ (inverse)
B$T = 2\pi/\omega$ (the period formula)
C$T = 1/\omega$ (frequency reciprocal)
D$T = \omega^2$ (squared)
Answer & Solution
Correct answer: B. $T = 2\pi/\omega$ (the period formula)
SHM: x(t) = A cos(ωt + φ). Period T = 2π/ω. Frequency f = ω/(2π) = 1/T.
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