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AP Calculus AB Unit 3B: Implicit Differentiation and Inverse Functions — practice questions

Explore 97 free Unit 3B: Implicit Differentiation and Inverse Functions questions in AP Calculus AB Mathematics. Open each question or exercise to read its content, reference answers and available explanation.

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Unit 3B: Implicit Differentiation and Inverse Functions questions and exercises with answers

Showing questions 1–30 of 97.

If z = cos(π/7) + i sin(π/7), then z⁷ equals:Read the answer and worked solution →For complex z, |z + i| = |z - i| describes:Read the answer and worked solution →|z|² = z × z̄. If |z|² = 4 and Re(z) = 1, then Im(z):Read the answer and worked solution →Find principal argument of -1 - i:Read the answer and worked solution →For roots of unity ω^n = 1: which is the SMALLEST n such that 1 + ω + ω² + ... + ω^(n-1) = 0?Read the answer and worked solution →Solve: z² + z + 1 = 0:Read the answer and worked solution →If z1, z2, z3 are vertices of an equilateral triangle, then:Read the answer and worked solution →Find (3 + 4i)/(1 + 2i):Read the answer and worked solution →The value of $i^2$ is:Read the answer and worked solution →If sin θ = 12/13 (acute θ in Q1), find tan(θ/2):Read the answer and worked solution →Find sin(15°):Read the answer and worked solution →cos(A + B) equals:Read the answer and worked solution →cos(90°) equals:Read the answer and worked solution →If tan θ = 1/2 (acute), find sin 2θ:Read the answer and worked solution →Minimum value of sin²θ + cos⁴θ:Read the answer and worked solution →The imaginary unit i is defined as:Read the answer and worked solution →For z = 3 + 4i, find |z|:Read the answer and worked solution →The conjugate of z = a + ib is:Read the answer and worked solution →i² + i³ equals:Read the answer and worked solution →In polar form z = r(cos θ + i sin θ), r is called the ___ and θ is the ___:Read the answer and worked solution →For z = a + ib, Re(z) and Im(z) are:Read the answer and worked solution →Compute (2 + i)(3 - 2i):Read the answer and worked solution →Find (1 + i)²:Read the answer and worked solution →Solve z² + 1 = 0:Read the answer and worked solution →Modulus of z1 z2 where z1 and z2 are complex:Read the answer and worked solution →Argument of z1 z2:Read the answer and worked solution →For z = 1 + i, find arg(z):Read the answer and worked solution →Find z̄ × z (where z = a + ib):Read the answer and worked solution →Convert i to polar form:Read the answer and worked solution →DeMoivre's theorem: (cos θ + i sin θ)ⁿ equals:Read the answer and worked solution →

Worked practice questions

If z = cos(π/7) + i sin(π/7), then z⁷ equals:

  1. i
  2. -1
  3. 1
  4. -i
Show answer and solution

Correct answer: B. -1

By DeMoivre: z⁷ = (cos π/7 + i sin π/7)⁷ = cos(π) + i sin(π) = -1 + 0i = -1.

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For complex z, |z + i| = |z - i| describes:

  1. A circle
  2. The real axis
  3. The imaginary axis
  4. Origin only
Show answer and solution

Correct answer: B. The real axis

Equidistant from i (= (0, 1)) and -i (= (0, -1)) means z lies on the perpendicular bisector — the real axis (y = 0).

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|z|² = z × z̄. If |z|² = 4 and Re(z) = 1, then Im(z):

  1. ±√3
  2. √3
  3. 2
  4. ±2
Show answer and solution

Correct answer: A. ±√3

|z|² = a² + b² = 4. With a = 1: b² = 3, so b = ±√3.

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