The unit digit of $7^{2026}$ is
- 1
- 7
- 3
- 9
Show answer and solution
Correct answer: D. 9
Unit digits of powers of 7 cycle with period 4: $7,9,3,1$.
Since $2026 \equiv 2 \pmod 4$, the unit digit matches $7^2 = 49$, i.e. 9.
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Correct answer: D. 9
Correct answer: D. $\dfrac{1}{x-1}$
Correct answer: A. 12
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