alleryDeMoivre's theorem: (cos θ + i sin θ)ⁿ equals:
Acosⁿ θ + i sinⁿ θ
Bcos θ + n i sin θ
Ccos(nθ) + i sin(nθ)
Dn(cos θ + i sin θ)
Answer & Solution
Correct answer: C. cos(nθ) + i sin(nθ)
**DeMoivre's theorem:** (cos θ + i sin θ)ⁿ = cos(nθ) + i sin(nθ) for any integer n.
Equivalent to (e^(iθ))ⁿ = e^(inθ).
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