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Andhra Pradesh SSC (Class 10) Statistics and Probability — practice questions

Explore 71 free Statistics and Probability questions in Andhra Pradesh SSC (Class 10) Mathematics. Open each question or exercise to read its content, reference answers and available explanation.

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Statistics and Probability questions and exercises with answers

Showing questions 1–30 of 71.

Harpreet tosses two different coins simultaneously. What is the probability of getting at least one head?Read the answer and worked solution →Savita and Hamida are friends. Ignoring leap year, what is the probability that they have the same birthday?Read the answer and worked solution →One card is drawn from a well-shuffled deck of 52 cards. What is the probability that the card is not an ace?Read the answer and worked solution →Which of the following is an impossible event when a fair die is thrown once?Read the answer and worked solution →If $P(E)=0.62$, what is $P(\overline{E})$?Read the answer and worked solution →A die is thrown once. What is the probability of getting a number greater than 4?Read the answer and worked solution →An event having only one outcome of an experiment is calledRead the answer and worked solution →The mean of grouped data by the direct method is:Read the answer and worked solution →The class mark of a class interval is:Read the answer and worked solution →The empirical relationship between the three measures of central tendency is:Read the answer and worked solution →The value that occurs most frequently in a data set is the:Read the answer and worked solution →The middle-most value of a data set arranged in order is the:Read the answer and worked solution →In the step-deviation method for the mean, $u_i$ is given by:Read the answer and worked solution →The mean of the first five natural numbers (1, 2, 3, 4, 5) is:Read the answer and worked solution →The class mark of the class interval 10–20 is:Read the answer and worked solution →The mode of the data 2, 3, 3, 4, 5 is:Read the answer and worked solution →The median of the data 3, 5, 7, 9 is:Read the answer and worked solution →The cumulative frequency of the last class interval equals:Read the answer and worked solution →The formula for the median of grouped data is:Read the answer and worked solution →If the mode is 12 and the mean is 15, then by the empirical formula the median is:Read the answer and worked solution →The theoretical probability of an event E is:Read the answer and worked solution →The probability of a sure (certain) event is:Read the answer and worked solution →The probability of an impossible event is:Read the answer and worked solution →The probability of any event E always lies between:Read the answer and worked solution →For any event E, the sum P(E) + P(not E) equals:Read the answer and worked solution →The probability of getting a head when an unbiased coin is tossed once is:Read the answer and worked solution →The probability of getting a 3 when a fair die is rolled once is:Read the answer and worked solution →The probability of getting an even number on a single roll of a fair die is:Read the answer and worked solution →The probability of drawing a red card from a well-shuffled deck of 52 cards is:Read the answer and worked solution →The probability of drawing an ace from a well-shuffled deck of 52 cards is:Read the answer and worked solution →

Worked practice questions

Harpreet tosses two different coins simultaneously. What is the probability of getting at least one head?

  1. $\frac{1}{4}$
  2. $\frac{1}{2}$
  3. $\frac{3}{4}$
  4. $1$
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Correct answer: C. $\frac{3}{4}$

The equally likely outcomes are $(H,H)$, $(H,T)$, $(T,H)$ and $(T,T)$. At least one head occurs in the first three outcomes, so there are 3 favourable outcomes out of 4. Thus the probability is $\frac{3}{4}$.

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Savita and Hamida are friends. Ignoring leap year, what is the probability that they have the same birthday?

  1. $\frac{1}{364}$
  2. $\frac{1}{365}$
  3. $\frac{364}{365}$
  4. $\frac{2}{365}$
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Correct answer: B. $\frac{1}{365}$

Fix Savita's birthday on any day. Hamida can have any of 365 equally likely birthdays, and only 1 of these matches Savita's. **So the probability of the same birthday is $\frac{1}{365}$.**

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One card is drawn from a well-shuffled deck of 52 cards. What is the probability that the card is not an ace?

  1. $\frac{1}{13}$
  2. $\frac{4}{13}$
  3. $\frac{12}{13}$
  4. $\frac{48}{13}$
Show answer and solution

Correct answer: C. $\frac{12}{13}$

A deck has 4 aces, so non-aces are $52-4=48$. Hence the probability is $\frac{48}{52}=\frac{12}{13}$. Equivalently, it is $1-\frac{1}{13}=\frac{12}{13}$.

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