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Harpreet tosses two different coins simultaneously. What is the probability of getting at least one head?
A$\frac{1}{4}$
B$\frac{1}{2}$
C$\frac{3}{4}$
D$1$
Answer & Solution
Correct answer: C. $\frac{3}{4}$
The equally likely outcomes are $(H,H)$, $(H,T)$, $(T,H)$ and $(T,T)$. At least one head occurs in the first three outcomes, so there are 3 favourable outcomes out of 4. Thus the probability is $\frac{3}{4}$.
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