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A die is thrown once. What is the probability of getting a number greater than 4?

A$\frac{1}{6}$
B$\frac{1}{3}$
C$\frac{1}{2}$
D$\frac{2}{3}$
Answer & Solution
Correct answer: B. $\frac{1}{3}$
The possible outcomes are $1,2,3,4,5,6$. Numbers greater than 4 are 5 and 6, so there are 2 favourable outcomes out of 6 total outcomes. **Thus $P=\frac{2}{6}=\frac{1}{3}$.**
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