Start learning →

Andhra Pradesh SSC (Class 10) Coordinate Geometry — practice questions

Explore 12 free Coordinate Geometry questions in Andhra Pradesh SSC (Class 10) Mathematics. Open each question or exercise to read its content, reference answers and available explanation.

Practise Coordinate Geometry with Quill →

Coordinate Geometry questions and exercises with answers

Showing questions 1–12 of 12.

If $A(6,1)$, $B(8,2)$, $C(9,4)$ and $D(p,3)$ are the vertices of a parallelogram taken in order, what is the value of $p$?Read the answer and worked solution →The midpoint of the line segment joining $(-6,10)$ and $(3,-8)$ isRead the answer and worked solution →The point dividing the line segment joining $(4,-3)$ and $(8,5)$ internally in the ratio $3:1$ isRead the answer and worked solution →A point on the $y$-axis is equidistant from $A(6,5)$ and $B(-4,3)$. What is that point?Read the answer and worked solution →If a point $P(x,y)$ is equidistant from $(7,1)$ and $(3,5)$, which relation must $x$ and $y$ satisfy?Read the answer and worked solution →The points $(3,2)$, $(-2,-3)$ and $(2,3)$ form which type of triangle?Read the answer and worked solution →What is the distance of the point $(-3,4)$ from the origin?Read the answer and worked solution →The distance between two points $P(x_1,y_1)$ and $Q(x_2,y_2)$ in the coordinate plane isRead the answer and worked solution →Distance between (1, 2) and (4, 6) equals:Read the answer and worked solution →Midpoint of A(2, 4) and B(6, 10) is:Read the answer and worked solution →CLASS10 · Mathematics · Distance Formula — Gap FillRead the answer and worked solution →CLASS10 · Mathematics · Section FormulaRead the answer and worked solution →

Worked practice questions

If $A(6,1)$, $B(8,2)$, $C(9,4)$ and $D(p,3)$ are the vertices of a parallelogram taken in order, what is the value of $p$?

  1. 5
  2. 6
  3. 7
  4. 8
Show answer and solution

Correct answer: C. 7

Principle: diagonals of a parallelogram bisect each other. 1. Midpoint of $AC$ is $\left(\dfrac{6+9}{2},\dfrac{1+4}{2}\right)=\left(\dfrac{15}{2},\dfrac{5}{2}\right)$. 2. Midpoint of $BD$ is $\left(\dfrac{8+p}{2},\dfrac{2+3}{2}\right)=\left(\dfrac{8+p}{2},\dfrac{5}{2}\right)$. 3. Since these midpoints are equal, $\dfrac{15}{2}=\dfrac{8+p}{2}$, so $15=8+p$ and hence $p=7$. Option D is tempting if one adds the last coordinates incorrectly, while A and B do not make the diagonal midpoints match.

Open this question →

The midpoint of the line segment joining $(-6,10)$ and $(3,-8)$ is

  1. $\left(-\dfrac{3}{2},1\right)$
  2. $\left(-\dfrac{3}{2},2\right)$
  3. $( -3,1)$
  4. $\left(\dfrac{3}{2},1\right)$
Show answer and solution

Correct answer: A. $\left(-\dfrac{3}{2},1\right)$

The midpoint formula gives $\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)$. **So the midpoint is $\left(\dfrac{-6+3}{2},\dfrac{10+(-8)}{2}\right)=\left(-\dfrac{3}{2},1\right)$.**

Open this question →

The point dividing the line segment joining $(4,-3)$ and $(8,5)$ internally in the ratio $3:1$ is

  1. $(7,3)$
  2. $(6,1)$
  3. $(5,-1)$
  4. $(8,3)$
Show answer and solution

Correct answer: A. $(7,3)$

Using the section formula, $x=\dfrac{3\cdot 8+1\cdot 4}{3+1}=7$ and $y=\dfrac{3\cdot 5+1\cdot(-3)}{3+1}=3$. **Hence the required point is $(7,3)$.**

Open this question →

How to practise

  1. Choose a Coordinate Geometry question and try to work out your answer.
  2. Open the question to check the correct answer and read its worked solution.
  3. Continue in the app for bite-sized lessons, explanations and review with Quill. You can start without creating an account.

Put it into practice

Continue with Coordinate Geometry practice for Andhra Pradesh SSC (Class 10). Read explanations as you go. No signup form needed to start.

Practise Coordinate Geometry →

More Mathematics topics

Real Numbers and PolynomialsArithmetic ProgressionStatistics and ProbabilityQuadratic EquationsLinear Equations in Two VariablesTriangles and CirclesIntroduction to TrigonometrySurface Areas and Volumes