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Andhra Pradesh SSC (Class 10) Arithmetic Progression — practice questions — page 4

Explore 95 free Arithmetic Progression questions in Andhra Pradesh SSC (Class 10) Mathematics. Open each question or exercise to read its content, reference answers and available explanation.

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Arithmetic Progression questions and exercises with answers

Showing questions 91–95 of 95.

Sum of all natural numbers between 100 and 200 divisible by 7 isRead the answer and worked solution →If a_n = 3 n + 5, the first three terms areRead the answer and worked solution →If sum of an AP is 100 and a = 5, l = 15, number of terms isRead the answer and worked solution →How many three-digit numbers are divisible by 6?Read the answer and worked solution →If S_n = n^2 + 3 n, then first term and common difference areRead the answer and worked solution →

Worked practice questions

Sum of all natural numbers between 100 and 200 divisible by 7 is

  1. 2087
  2. 2100
  3. 2110
  4. 2107
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Correct answer: D. 2107

1. First multiple above 100 is 105; last below 200 is 196. 2. n = (196 - 105)/7 + 1 = 14. 3. S_14 = 14/2 * (105 + 196) = 7 * 301. 4. = 2107. _Source: Selina Concise Mathematics Class 10, Ch on Arithmetic Progression (Mistral OCR'd PDF), section on sum problems_

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If a_n = 3 n + 5, the first three terms are

  1. 8, 11, 14
  2. 5, 8, 11
  3. 3, 6, 9
  4. 8, 13, 18
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Correct answer: A. 8, 11, 14

1. Plug n = 1: a_1 = 3 + 5 = 8. 2. n = 2: a_2 = 6 + 5 = 11. 3. n = 3: a_3 = 9 + 5 = 14. 4. So the AP starts 8, 11, 14. _Source: Selina Concise Mathematics Class 10, Ch on Arithmetic Progression (Mistral OCR'd PDF), section on nth term formula_

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If sum of an AP is 100 and a = 5, l = 15, number of terms is

  1. 8
  2. 10
  3. 12
  4. 15
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Correct answer: B. 10

1. Use S_n = n/2 * (a + l). 2. 100 = n/2 * (5 + 15) = n/2 * 20 = 10 n. 3. So n = 10. 4. Hence there are 10 terms. _Source: Selina Concise Mathematics Class 10, Ch on Arithmetic Progression (Mistral OCR'd PDF), section on sum formula_

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