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Sum of all natural numbers between 100 and 200 divisible by 7 is
A2087
B2100
C2110
D2107
Answer & Solution
Correct answer: D. 2107
1. First multiple above 100 is 105; last below 200 is 196.
2. n = (196 - 105)/7 + 1 = 14.
3. S_14 = 14/2 * (105 + 196) = 7 * 301.
4. = 2107.
_Source: Selina Concise Mathematics Class 10, Ch on Arithmetic Progression (Mistral OCR'd PDF), section on sum problems_
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