Bohr's postulate quantises the angular momentum of an electron in a stationary orbit as
A$L = \tfrac{\hbar}{n}$
B$L = nh^2$
C$L = n\hbar$
D$L = nh$
Answer & Solution
Correct answer: C. $L = n\hbar$
Bohr postulated $L = mvr = n\hbar = \tfrac{nh}{2\pi}$ for positive integers $n$. Option A is off by a factor of $2\pi$ — a classic distractor.
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