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A stopping potential of 1.5 V means the fastest photoelectrons carry
A2.4 x 10^-19 J
B1.5 x 10^-19 J
C1.1 x 10^-19 J
D3.0 x 10^-19 J
Answer & Solution
Correct answer: A. 2.4 x 10^-19 J
Kmax = eV0 = 1.602 x 10^-19 C x 1.5 V, which is about 2.4 x 10^-19 J.
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