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Light of wavelength 400 nm falls on a metal of work function 2.1 eV. Kmax is about
A0.5 eV
B3.1 eV
C1.0 eV
D2.1 eV
Answer & Solution
Correct answer: C. 1.0 eV
Photon energy is 1240 eV nm / 400 nm = 3.1 eV, and 3.1 - 2.1 leaves 1.0 eV.
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