Two point charges of $+4\ \mu$C each are separated by $0.6$ m in vacuu…

Question

Two point charges of $+4\ \mu$C each are separated by $0.6$ m in vacuum. The magnitude of the electrostatic force between them is approximately: (Take $k = 9 	imes 10^9\ \mathrm{N\,m^2/C^2}$.)

Accepted Answer

A. $0.4$ N

Coulomb's law: $F = \dfrac{k q_1 q_2}{r^2} = \dfrac{9 	imes 10^9 	imes (4 	imes 10^{-6})^2}{(0.6)^2} = \dfrac{9 	imes 10^9 	imes 16 	imes 10^{-12}}{0.36} = \dfrac{0.144}{0.36} = 0.4$ N.

Answer

$4.0$ N

Answer

$0.1$ N

Answer

$1.0$ N

Two point charges of $+4\ \mu$C each are separated by $0.6$ m in vacuum. The magnitude of the electrostatic force between them is approximately: (Take $k = 9 \times 10^9\ \mathrm{N\,m^2/C^2}$.)