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Two charges +q and −q of equal magnitude are placed at the corners A and B of an equilateral triangle. The net electric field at the third corner C
A{'text': 'Is zero', 'label': 'A'}
B{'text': 'Points along the perpendicular bisector of AB (parallel to BA direction)', 'label': 'B'}
C{'text': 'Is along the direction from A to B (parallel to +q to −q)', 'label': 'C'}
D{'text': 'Is radially outward from C', 'label': 'D'}
Answer & Solution
Correct answer: C. {'text': 'Is along the direction from A to B (parallel to +q to −q)', 'label': 'C'}
1. Field at C due to +q at A points from A toward C.
2. Field at C due to −q at B points from C toward B.
3. Vector sum has cancellations along the perpendicular bisector of AB and a residual along BA direction.
4. Net field lies along the direction A → B, i.e., from +q toward −q.
_Source: NCERT Class 12 Physics, Ch 1 "Electric Charges and Fields", §1.6_
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