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If a positive point charge is placed at the centre of a spherical conducting shell of radius R (neutral), the field inside the shell (r < R) due to the charge is

A{'text': 'Zero', 'label': 'A'}
B{'text': 'Depends only on shell material', 'label': 'B'}
C{'text': 'Non-zero and pointing radially outward', 'label': 'C'}
D{'text': 'Points toward the shell surface always', 'label': 'D'}
Answer & Solution
Correct answer: C. {'text': 'Non-zero and pointing radially outward', 'label': 'C'}
1. Field inside a Gaussian sphere at radius r < R (encloses only the central charge q) is E = k q / r² radially outward. 2. Induced charge on the inner surface of the conducting shell (−q) does not add to the field at r < R. 3. So the field inside the shell is fully due to the central charge, radially outward. 4. Only the outside field E(r > R) sees the full net charge on the outer surface. _Source: NCERT Class 12 Physics, Ch 1 "Electric Charges and Fields", §1.11_
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