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A binary string of length 5 is randomly chosen. P(exactly 3 zeros):
A1/2
BC(5,3) × (1/2)⁵ = 10/32 = 5/16
C10/32
D3/5
Answer & Solution
Correct answer: B. C(5,3) × (1/2)⁵ = 10/32 = 5/16
Binomial: P(exactly 3 zeros in 5 trials, each P=1/2): C(5,3) × 0.5⁵ = 10/32 = 5/16.
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