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CAT Quantitative Aptitude — practice by topic

Browse 494 questions across 30 Quantitative Aptitude topics. Choose what you want to revise, then open a question to check its answer and worked solution.

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Quantitative Aptitude topics

Quantitative Aptitude (398)Algebra (201)CAT QA — Mixed (43)Profit and Loss (39)Ratio and Proportion (39)Time and Work (35)Percentages (31)Averages and Mixtures (30)DI — Tables (30)Geometry (30)Geometry & Mensuration (30)Modern Mathematics (30)Number System (30)Probability (30)Coordinate Geometry (29)HCF and LCM (29)Progressions (29)Inequalities (27)Quadratic Equations (27)Speed Distance (22)Time Speed and Distance (22)Averages (10)Interest (9)Simple & Compound Interest (9)Simple Interest (9)Geometry and Mensuration (1)Logarithms (1)Number Theory (1)Ratios (1)Speedanddistance (1)

Try a Quantitative Aptitude question

In how many ways can the letters of the word EQUATION be arranged?Read the answer and worked solution →The number of arrangements of letters of the word MISSISSIPPI is:Read the answer and worked solution →How many 5-digit numbers can be formed using digits 1-9 (no repetition)?Read the answer and worked solution →From 10 boys and 8 girls, a committee of 5 is to be formed with exactly 3 boys. Number of ways:Read the answer and worked solution →

Worked practice questions

In how many ways can the letters of the word EQUATION be arranged?

  1. 8! = 40320
  2. 7! = 5040
  3. 8 × 7
  4. 8!/2! = 20160
Show answer and solution

Correct answer: A. 8! = 40320

EQUATION has 8 distinct letters (E,Q,U,A,T,I,O,N — all different). Number of arrangements = 8! = 40320.

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The number of arrangements of letters of the word MISSISSIPPI is:

  1. 11!/(4! × 4! × 2!) = 34650
  2. 11
  3. 11!/4!
  4. 11!
Show answer and solution

Correct answer: A. 11!/(4! × 4! × 2!) = 34650

**MISSISSIPPI has 11 letters:** M(1), I(4), S(4), P(2). **Arrangements with repetition:** 11!/(1! × 4! × 4! × 2!) = 39916800/(1 × 24 × 24 × 2) = 39916800/1152 = 34650.

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How many 5-digit numbers can be formed using digits 1-9 (no repetition)?

  1. 5!
  2. 9P5 = 9!/4! = 15120
  3. 9 × 5
  4. 9⁵
Show answer and solution

Correct answer: B. 9P5 = 9!/4! = 15120

9 choices for 1st digit, 8 for 2nd, ..., 5 for 5th. 9P5 = 9 × 8 × 7 × 6 × 5 = 15120.

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