Home › CAT › Quantitative Aptitude › CAT QA — Mixed › P(A) = 0.6, P(B) = 0.5, P(A ∩ B) = 0.3. P(A | B):
P(A) = 0.6, P(B) = 0.5, P(A ∩ B) = 0.3. P(A | B):
A0.5
B0.6
C0.3
DP(A∩B)/P(B) = 0.3/0.5 = 0.6
Answer & Solution
Correct answer: D. P(A∩B)/P(B) = 0.3/0.5 = 0.6
Conditional probability: P(A|B) = P(A ∩ B)/P(B) = 0.3/0.5 = 0.6. Coincidentally equal to P(A), implying A and B are independent.
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