Start learning →

The 20th term of the AP 3, 7, 11, 15, ... is:

A80
B75
C83
D79 (a=3, d=4; a_n = 3 + 19×4 = 79)
Answer & Solution
Correct answer: D. 79 (a=3, d=4; a_n = 3 + 19×4 = 79)
**AP:** a = 3, d = 4. a_n = a + (n-1)d. We have a_20 = 3 + 19(4). That is a_20 = 3 + 76. So a_20 = 79.
Practise this question with Quill — CAT →

Keep practising CAT QA — Mixed

Browse all CAT QA — Mixed questions for CAT, or explore more Quantitative Aptitude topics.

Start a CAT QA — Mixed lesson →
Related questions
Pythagorean triplet (3, 4, ?): missing value:Volume of a cylinder with radius 3 and height 10:Circumference of circle with radius 7:Geometry: Area of equilateral triangle with side 6 cm:Remainder when 7^100 is divided by 5:If log_2(x) = 5, then x =Log base 10 of 1000:Sum and product of roots of x² + 7x + 12 = 0: