How many 5-digit numbers can be formed using digits 1-9 (no repetition)?
A5!
B9P5 = 9!/4! = 15120
C9 × 5
D9⁵
Answer & Solution
Correct answer: B. 9P5 = 9!/4! = 15120
9 choices for 1st digit, 8 for 2nd, ..., 5 for 5th.
9P5 = 9 × 8 × 7 × 6 × 5 = 15120.
Keep practising CAT QA — Mixed
Browse all CAT QA — Mixed questions for CAT, or explore more Quantitative Aptitude topics.
Related questions
Pythagorean triplet (3, 4, ?): missing value:Volume of a cylinder with radius 3 and height 10:Circumference of circle with radius 7:Geometry: Area of equilateral triangle with side 6 cm:Remainder when 7^100 is divided by 5:If log_2(x) = 5, then x =Log base 10 of 1000:Sum and product of roots of x² + 7x + 12 = 0: