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Why is Stokes terminal speed proportional to R squared?

ABuoyancy beats weight
BNet weight ~ R^3, drag ~ R
CDrag ~ R^3, net weight ~ R
DWeight and drag both ~ R
Answer & Solution
Correct answer: B. Net weight ~ R^3, drag ~ R
Weight minus buoyancy rises with R cubed while drag rises only with R, so the balancing speed scales as R squared.
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