A reaction has ∆H = +40 kJ/mol and ∆S = +100 J/K mol. It becomes spontaneous above:
A400 K
B40 K
C250 K
D4000 K
Answer & Solution
Correct answer: A. 400 K
∆G turns negative when T > ∆H/∆S = 40000/100 = 400 K.
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