Start learning →

Two moles of ideal gas expand reversibly at 300 K to ten times their volume. Work done w?

A-4.99 kJ
B-11.49 kJ
C-5.74 kJ
D+11.49 kJ
Answer & Solution
Correct answer: B. -11.49 kJ
w = -2.303 nRT log(Vf/Vi) = -2.303 x 2 x 8.314 x 300 x 1 = -11488 J, about -11.49 kJ.
Practise this question with Quill — NEET UG →

Keep practising Thermodynamics

Browse all Thermodynamics questions for NEET UG, or explore more Chemistry topics.

Start a Thermodynamics lesson →