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At 298 K, 4Fe + 3O2 → 2Fe2O3 has ∆rS = -549.4 J/K mol and ∆rH = -1648 kJ/mol. ∆Stotal?

A+5530.0 J/K mol
B-6079.4 J/K mol
C+4980.6 J/K mol
D-549.4 J/K mol
Answer & Solution
Correct answer: C. +4980.6 J/K mol
∆Ssurr = 1648000/298 = 5530 J/K mol, and adding -549.4 gives +4980.6 J/K mol, so rusting is spontaneous.
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