alleryHCl(g) + 10 aq has ∆H -69.01; + 25 aq has -72.03 kJ/mol. ∆H of HCl.10aq + 15 aq?
A-3.02 kJ/mol
B-141.04 kJ/mol
C+3.02 kJ/mol
D-72.03 kJ/mol
Answer & Solution
Correct answer: A. -3.02 kJ/mol
Subtracting the two equations gives ∆H = -72.03 - (-69.01) = -3.02 kJ/mol for the dilution.
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