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A gas expands by 2 x 10^-3 m^3 against a steady pressure of 10^5 Pa. Work done by the gas is

A2000 J
B20 J
C200 J
D50 J
Answer & Solution
Correct answer: C. 200 J
Work against constant pressure is P times change in volume = 10^5 x 2 x 10^-3 = 200 J.
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