ꯀꯔꯤꯒꯨꯝꯕꯥ $a + b + c = 0$ ꯑꯣꯏꯔꯕꯗꯤ, $a^3 + b^3 + c^3$ꯒꯤ ꯚꯦꯜꯌꯨ ꯑꯁꯤ ꯀꯌꯥꯅꯣ?
A$3abc$
B$-3abc$
C$0$
D$abc$
Answer & Solution
Correct answer: A. $3abc$
ꯑꯥꯏꯗꯦꯟꯇꯤꯇꯤ $a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)$ ꯑꯁꯤ $a+b+c=0$ ꯇꯧꯕꯥ ꯃꯇꯃꯗꯥ ꯔꯥꯏꯠ-ꯍꯦꯟꯗ ꯁꯥꯏꯗ ꯖꯤꯔꯣ ꯂꯩ꯫ ꯃꯔꯝ ꯑꯗꯨꯅꯥ $a^3+b^3+c^3=3abc$, ꯃꯔꯝ ꯑꯗꯨꯅꯥ ꯑꯣꯄꯁꯟ A ꯑꯁꯤ ꯑꯆꯨꯝꯕꯅꯤ꯫ ꯁꯣꯝ ꯑꯁꯤ ꯖꯤꯔꯣ ꯑꯣꯏꯕꯅꯥ ꯃꯁꯥ ꯃꯊꯟꯇꯥ ꯀ꯭ꯌꯨꯕꯁꯤꯡꯒꯤ ꯁꯣꯝ ꯑꯁꯤ ꯖꯤꯔꯣꯅꯤ ꯍꯥꯌꯕꯥ ꯇꯥꯀꯄꯥ ꯅꯠꯇꯦ꯫
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