alleryRydberg formula for hydrogen lines:
Aλ = R × n × Z
Bλ = R n²
C1/λ = R (1/n₁² - 1/n₂²) (R ≈ 1.097 × 10⁷ /m, n₂ > n₁)
DE = R × λ
Answer & Solution
Correct answer: C. 1/λ = R (1/n₁² - 1/n₂²) (R ≈ 1.097 × 10⁷ /m, n₂ > n₁)
1/λ = R (1/n₁² - 1/n₂²).
R is Rydberg constant = 1.097 × 10⁷ /m.
For Hα (Balmer α, n₂=3 to n₁=2): 1/λ = R(1/4 - 1/9) = 5R/36 → λ ≈ 656 nm (red).
Keep practising Atoms and Nuclei
Browse all Atoms and Nuclei questions for JEE Advanced, or explore more Physics topics.
Related questions
The de Broglie wavelength $\lambda$ of an electron in the $n$th Bohr orbit of hydrogen, inThe radius of the $n$th Bohr orbit in a hydrogen-like atom of nuclear charge $Z$ scales asComplete Bohr's first postulateSpot the one that does not belongOrder the atomic models in this chapterSpot the one that does not belongTrue or false: Rutherford's two difficultiesOrder the argument: why Rutherford's atom should collapse