Rydberg formula for hydrogen lines:
Aλ = R × n × Z
Bλ = R n²
C1/λ = R (1/n₁² - 1/n₂²) (R ≈ 1.097 × 10⁷ /m, n₂ > n₁)
DE = R × λ
Answer & Solution
Correct answer: C. 1/λ = R (1/n₁² - 1/n₂²) (R ≈ 1.097 × 10⁷ /m, n₂ > n₁)
1/λ = R (1/n₁² - 1/n₂²). R is Rydberg constant = 1.097 × 10⁷ /m. For Hα (Balmer α, n₂=3 to n₁=2): 1/λ = R(1/4 - 1/9) = 5R/36 → λ ≈ 656 nm (red).
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