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HomeJEE MainPhysicsAtoms and Nuclei › For He⁺ ion (Z = 2), energy of n=1 (ground state):

For He⁺ ion (Z = 2), energy of n=1 (ground state):

ASame as H
B-13.6 eV
C-13.6 / 4
D-13.6 × Z²/n² = -54.4 eV
Answer & Solution
Correct answer: D. -13.6 × Z²/n² = -54.4 eV
For hydrogen-like ion (one electron): E_n = -13.6 × Z²/n² eV. For He⁺ (Z = 2), n = 1: -13.6 × 4 = -54.4 eV. Bound much more strongly than H (4× more).
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