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The point on the y-axis equidistant from (6, 5) and (minus 4, 3) is:
A(0, 5)
B(0, 3)
C(0, 9)
D(0, 7)
Answer & Solution
Correct answer: C. (0, 9)
1. Any point on the y-axis is (0, y).
2. Equating the two squared distances gives y equal to 9.
3. The point is (0, 9).
_Source: NCERT Class 10 Mathematics, Chapter 7, Coordinate Geometry._
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