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The sum of the first n terms of a progression can be written as n by 2 times:
A2a times (n minus 1) d
B2a plus (n minus 1) d
C2a plus (n plus 1) d
D2a minus (n plus 1) d
Answer & Solution
Correct answer: B. 2a plus (n minus 1) d
1. The first term appears twice in the bracket.
2. The rest of the bracket counts the steps.
3. It is 2a plus (n minus 1) d.
_Source: NCERT Class 10 Mathematics, Chapter 5, Arithmetic Progressions._
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