alleryDistance from point (1, 2, 3) to plane x + y + z = 0:
A6
B6/sqrt(3) = 2 sqrt(3)
C0
Dsqrt(3)
Answer & Solution
Correct answer: B. 6/sqrt(3) = 2 sqrt(3)
Distance from (x₀, y₀, z₀) to ax+by+cz=d is |ax₀+by₀+cz₀-d|/sqrt(a²+b²+c²) = |1+2+3-0|/sqrt(3) = 6/sqrt(3) = 2 sqrt(3) ≈ 3.46.
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