When subtracting vectors, $\vec A-\vec B$ is evaluated as
A$\vec A + \vec B$
B$\vec B + (-\vec A)$
C$\vec A + (-\vec B)$
D$(-\vec A) + (-\vec B)$
Answer & Solution
Correct answer: C. $\vec A + (-\vec B)$
Vector subtraction is performed by reversing the direction of the vector being subtracted and then adding.
**Hence $\vec A-\vec B = \vec A + (-\vec B)$.**
Keep practising Unit 8A: Areas Between Curves
Browse all Unit 8A: Areas Between Curves questions for AP Calculus AB, or explore more Mathematics topics.
Related questions
Let $\mathbf{A}=\langle 1,2,3\rangle$, $\mathbf{B}=\langle 2,0,1\rangle$, and $\mathbf{C}=For nonzero vector $\mathbf{A}$, which expression gives a vector in the same direction as The projection of vector $\vec A$ on vector $\vec B$ is given byWhich statement about a null vector is correct?If $\omega$ is a non-real cube root of unity, find the value of $1 + \omega + \omega^2$.Find the modulus of the complex number $z = 3 + 4i$.The locus of the point $z$ in the Argand plane satisfying $|z - 2| = |z + 2|$ is:Evaluate $\displaystyle\lim_{x \to 0} \dfrac{1 - \cos 2x}{x^2}$.