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Normal vector to plane ax + by + cz = d is:
A(a, b, c)
B(1, 1, 1)
C(0, 0, 1)
DRandom
Answer & Solution
Correct answer: A. (a, b, c)
Coefficients (a, b, c) of plane equation give direction of normal vector. Perpendicular distance from origin = |d|/sqrt(a²+b²+c²).
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