Ionization enthalpy comparison: O vs F. The 1st IE of O is LESS than that of N (because O has paired 2p electron easier to remove). Similarly:
AS > P
BSame
CS < P
DCannot say
Answer & Solution
Correct answer: C. S < P
**Anomaly:** 1st IE of O < N due to paired electron destabilization in O (2p⁴ vs N's stable 2p³ half-filled).
**Same in 3rd row:** S (3p⁴) < P (3p³).
**Similar in row 4:** Se < As, Te < Sb.
**General:** half-filled subshells are especially stable.
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