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Ignoring a leap year, the probability that two friends have different birthdays is:

A1/365
B365/364
C1/364
D364/365
Answer & Solution
Correct answer: D. 364/365
1. One friend's birthday can be any day. 2. The other must avoid that one day. 3. So 364 out of 365 days work. _Source: syllabus Mathematics, Chapter 15, Probability._
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