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Counting eggs that leave remainders 1, 2, 3, 4, 5 in pairs, threes, fours, fives, sixes and none in sevens, under 150, gives:

A105
B140
C91
D119
Answer & Solution
Correct answer: D. 119
1. Look for multiples of 7 that fit every condition. 2. Use the idea of LCM. 3. The answer is 119 eggs. _Source: syllabus Mathematics, Chapter 1, Real Numbers._
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